t^2+16t+32=0

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Solution for t^2+16t+32=0 equation:


Simplifying
t2 + 16t + 32 = 0

Reorder the terms:
32 + 16t + t2 = 0

Solving
32 + 16t + t2 = 0

Solving for variable 't'.

Begin completing the square.

Move the constant term to the right:

Add '-32' to each side of the equation.
32 + 16t + -32 + t2 = 0 + -32

Reorder the terms:
32 + -32 + 16t + t2 = 0 + -32

Combine like terms: 32 + -32 = 0
0 + 16t + t2 = 0 + -32
16t + t2 = 0 + -32

Combine like terms: 0 + -32 = -32
16t + t2 = -32

The t term is 16t.  Take half its coefficient (8).
Square it (64) and add it to both sides.

Add '64' to each side of the equation.
16t + 64 + t2 = -32 + 64

Reorder the terms:
64 + 16t + t2 = -32 + 64

Combine like terms: -32 + 64 = 32
64 + 16t + t2 = 32

Factor a perfect square on the left side:
(t + 8)(t + 8) = 32

Calculate the square root of the right side: 5.656854249

Break this problem into two subproblems by setting 
(t + 8) equal to 5.656854249 and -5.656854249.

Subproblem 1

t + 8 = 5.656854249 Simplifying t + 8 = 5.656854249 Reorder the terms: 8 + t = 5.656854249 Solving 8 + t = 5.656854249 Solving for variable 't'. Move all terms containing t to the left, all other terms to the right. Add '-8' to each side of the equation. 8 + -8 + t = 5.656854249 + -8 Combine like terms: 8 + -8 = 0 0 + t = 5.656854249 + -8 t = 5.656854249 + -8 Combine like terms: 5.656854249 + -8 = -2.343145751 t = -2.343145751 Simplifying t = -2.343145751

Subproblem 2

t + 8 = -5.656854249 Simplifying t + 8 = -5.656854249 Reorder the terms: 8 + t = -5.656854249 Solving 8 + t = -5.656854249 Solving for variable 't'. Move all terms containing t to the left, all other terms to the right. Add '-8' to each side of the equation. 8 + -8 + t = -5.656854249 + -8 Combine like terms: 8 + -8 = 0 0 + t = -5.656854249 + -8 t = -5.656854249 + -8 Combine like terms: -5.656854249 + -8 = -13.656854249 t = -13.656854249 Simplifying t = -13.656854249

Solution

The solution to the problem is based on the solutions from the subproblems. t = {-2.343145751, -13.656854249}

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